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shepuryov [24]
3 years ago
6

Please answer for points and brainlyest:3

Mathematics
2 answers:
elena-s [515]3 years ago
5 0

Answer:

60w  <--------- Equation

Step-by-step explanation:

For number 2 the answer is $900

Svetlanka [38]3 years ago
5 0

Answer:

answer to part a)

         (125+25w)+(225+35w)

answer to part b)

         1250$ in both accounts together

Step-by-step explanation:

 (125+25*15)+(225+35*15) = 1250

Hope this helps! <3

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Find the volume of each prism. Round to the nearest tenth if necessary. (Please give explanation if you can)
Gnom [1K]

Answer:9

Step-by-step explanation:

Because things are better guessed

4 0
3 years ago
Find the midpoint between the points (7, -2) and (-4, 2). Write your answer in the proper form using parentheses
Elan Coil [88]

Answer:

( 1.5, 0)

Step-by-step explanation:

1. Find the coordinates ; in this case (7,-2) and (-4, 2)

2. Plug it into the formula (x1 + x2 ÷ 2 ) , (y1 + y2 ÷ 2)

3. ( 7 +  -4 ÷2) = 1.5    And    ( -2 + 2 ÷ 2) = 0

4. Therefore, the midpoint is ( 1.5, 0 )

                                         

3 0
3 years ago
The equation of a line is given below. 6x -4y = 24. Find the x-intercept and the Y-intercept then use them to graph the line
ipn [44]

Answer:

x intercept is 4 and the y intercept is -6

Step-by-step explanation:

x-int:

6x=24

x=4

y-int:

-4y=24

y=-6

5 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
For Which Value of P and W is P+W a rational number. Tell me how you got that answer
Ymorist [56]
300.02 if you use the square root of 72
6 0
3 years ago
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