72% can also be written as 0.72, so take 0.72 x 45 = 32.4
Subtract 32.4 from 45 45 - 32.4 = 12.6 You need 12.6 renewals in 5 days.
Answer:
Step-by-step explanation:
a) The formula for determining the standard error of the distribution of differences in sample proportions is expressed as
Standard error = √{(p1 - p2)/[(p1(1 - p1)/n1) + p2(1 - p2)/n2}
where
p1 = sample proportion of population 1
p2 = sample proportion of population 2
n1 = number of samples in population 1,
n2 = number of samples in population 2,
From the information given
p1 = 0.77
1 - p1 = 1 - 0.77 = 0.23
n1 = 58
p2 = 0.67
1 - p2 = 1 - 0.67 = 0.33
n2 = 70
Standard error = √{(0.77 - 0.67)/[(0.77)(0.23)/58) + (0.67)(0.33)/70}
= √0.1/(0.0031 + 0.0032)
= √1/0.0063
= 12.6
the standard error of the distribution of differences in sample proportions is 12.6
b) the sample sizes are large enough for the Central Limit Theorem to apply because it is greater than 30
Answer:
j) y=2/5x-1
Step-by-step explanation:
you can use desmos graphing calculator to help you on questions like these, all you gotta do is input each answer and you get a visual representation of what they look like. Hope this helps!
Answer:
0.97
Step-by-step explanation:
Given that a homeowner has two smoke detector alarms installed, one in the dining room (adjacent to the kitchen) and one in an upstairs bedroom (above the kitchen). If cooking produces smoke in the kitchen, the probability of setting off the dining room alarm (D) is .95. The probability of setting off the bedroom alarm (B) is .40.
Both alarms are independent of each other.
Probability for smoke detection=P(any one alarm rings)
=P(Kitchen alarm sets off)+P(bed room alarm sets off)-P(Both sets off)
Since both are independent
P(Both) =
Probability for smoke detection
= 0.95+0.40-0.38
=0.97
As we look, line TU = 16. But, there are two lines right below it, and there are two lines on the line UW. Now, all that this means is UW is the same length as TU.
Since we know what TU and UW is and we need to add them together to find the total length of the line TW.
16 + 16 = 32.
Therefore, the length of line TW is 32 units long.
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