Question

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Answer 1

Answer:

$P(Sum = 9) = \frac{1}{9}$

Step-by-step explanation:

Given

Outcomes of rolling two dice

Required

P(Sum = 9)

From the given outcomes, we have:

$n(S) = 36$ -- the sample size

$Sum = 9:=\{(3,6),(4,5),(5,4),(6,3)\}$

So.

$n(Sum = 9) = 4$

The probability is:

$P(Sum = 9) = \frac{n(Sum = 9)}{n(S)}$

$P(Sum = 9) = \frac{4}{36}$

Simplify

$P(Sum = 9) = \frac{1}{9}$