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Naddika [18.5K]
3 years ago
6

????????????????????????

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

P(Sum = 9) = \frac{1}{9}

Step-by-step explanation:

Given

Outcomes of rolling two dice

Required

P(Sum = 9)

From the given outcomes, we have:

n(S) = 36 -- the sample size

Sum = 9:=\{(3,6),(4,5),(5,4),(6,3)\}

So.

n(Sum = 9) = 4

The probability is:

P(Sum = 9) = \frac{n(Sum = 9)}{n(S)}

P(Sum = 9) = \frac{4}{36}

Simplify

P(Sum = 9) = \frac{1}{9}

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notsponge [240]

Answer:

She teaches 6 classes

5 0
3 years ago
5th grade math. correct answer will be marked brainliest
kipiarov [429]
The correct answer is 67 ur welcome
4 0
3 years ago
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Consider the first four terms of the sequence below.
Lelu [443]

Answer:

a₈ = -  1 / 128

Step-by-step explanation:

Given:

First four terms of the sequence

a₁= 1, a₂= - 1/2, a₃= 1/4 and a₄= -1/8

First we recognize that this is a geometric series (sequence) and we must calculate quotient q.

q = a₂/a₁ = a₃/a₂ = (-1/2)/1 = (1/4)/(-1/2) = - 1/2

q = - 1/2

Formula for calculating n-th term is:

aₙ = a₁ · qⁿ⁻¹

According to this:

a₈ = 1  (-1/2)⁷ = - 1/ 128

God with you!!!

8 0
3 years ago
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
4 years ago
17 percent of what is 40<br>45 of 155 is what<br>What percent of 153 is 137<br>​
Keith_Richards [23]

Answer:

Number 1 :If you are using a calculator, simply enter 40×100÷17, which will give you the answer.

Number 2: 45 percent of 155 is 69.75.

Number 3: 137 is what percent of 153? = 89.54

3 0
3 years ago
Read 2 more answers
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