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Temka [501]
3 years ago
11

In which quadrant is point F located? III I II IV

Mathematics
2 answers:
egoroff_w [7]3 years ago
8 0
F is located in |||

i needed more characters
Tanzania [10]3 years ago
6 0

Answer:

quadrant III

Step-by-step explanation:

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x = 3

Step-by-step explanation:

\sin \: 45 \degree =  \frac{BC}{6 \sqrt{2} }  \\  \\  \frac{1}{ \sqrt{2} } =  \frac{BC}{6 \sqrt{2} }  \\  \\ BC = 6 \\  \\  \cos \: 60 \degree =  \frac{x}{BC }  \\  \\   \frac{1}{2}  =  \frac{x}{6 }   \\  \\ x =  \frac{6}{2}  \\  \\ x = 3

7 0
3 years ago
PLEASE ANSWER QUICKLY<br> (I will give first answer Brainliest)
Zina [86]

Answer:

The measure of Angle A is 45.5 degrees

Step-by-step explanation:

In order to find the measure of the angle A, add it to the measures of angle B and C. Since it is an isosceles triangle, we know that B and C have the same measure. Then we set this equal to 180.

A + B + C = 180

2x + 4 + 3x + 5 + 3x + 5 = 180

8x + 14 = 180

8x = 166

x = 20.75

Now we can find the measure of Angle A by putting the value of x in for x.

2x + 4 = A

2(20.75) + 4 = A

41.5 + 4 = A

45.5 = A

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What's the answer to 26×10 squared
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For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
3 years ago
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