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kipiarov [429]
3 years ago
15

1) 5k = 27 Solve equation and proportion

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

k = 27/5

Step-by-step explanation:

Divide 5 on bot sides

5k/5 = 27/5

k= 27/5

so, k = 27/5 OR 5.4

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What is 5a-5=7+2a also explain it
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5a-5=7+2a -- we need to isolate a. Subtract 2a from both sides

3a-5=7 -- add 5 to both sides
3a=12 -- divide by 3

a=4

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Start at $82 and count to $512
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The easiest way is to count by 1 starting from 82 till you reach 512.

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Perform the following division: (–1/6) ÷ (–3/7) A. –7/18 B. 7/18 C. –3/42 D. 3/42
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Answer:

B. 7/18

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Lily spent 1/6 of her free time practicing soccer and 3 of her
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4 years ago
A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp
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Answer:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

Step-by-step explanation:

Information given

\bar X=98.90 represent the sample mean

\mu population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=103-1=102

Since the Confidence is 0.95 or 95%, the significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value for this case would be t_{\alpha/2}=1.984

And replacing we got:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

8 0
3 years ago
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