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IrinaK [193]
3 years ago
14

Um can someone help me with a question? (theres an attachment with the question there)

Mathematics
1 answer:
Ugo [173]3 years ago
4 0
She needs 15 cans of varnish
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the length of a rectangle is 2ft more than twice the width. The area is 180 ft^2. find the length and width of the rectangle
Mariana [72]

Answer:

Area = length * width

 

112 = (2w+2)*w

 

112 = 2w^2 + 2w

 

0 =2w^2 + 2w - 112

 

0 = w^2 + w - 56

 

0 = (  w  +  8  )( w  -    7  )

 

w+8=0  results in negative measures

 

w-7=0 --> w = 7

 

width is 7

length is 16

3 0
2 years ago
How do you graph y=8.5x
vladimir1956 [14]

Answer:

You graph in the middle of the box

Step-by-step explanation:

go up 8 and to the right of box half way in the middle

8 0
3 years ago
I need help asap plsss
Sergio [31]

Radius = 5 cm

Height = 8 cm

Volume = πr²h

Volume = π(5 cm)² × 8 cm

Volume = π × 25 cm² × 8 cm

Volume = 200π cm³

6 0
3 years ago
Read 2 more answers
I need help graphing
steposvetlana [31]

Lmk if this helped if not im sorry

5 0
3 years ago
Need help on these math questions. please and thank u
Svetach [21]

9514 1404 393

Answer:

  a) x = -3

  b) y = (28/27)x -27

Step-by-step explanation:

a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...

  x = constant

For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...

  x = -3

__

b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...

  m = -1/(-27/28) = 28/27

Using the point-slope equation for a line, we can model Ace Rd as ...

  y -y1 = m(x -x1)

  y -1 = (28/27)(x -27)

  y = (28/27)x -27

4 0
3 years ago
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