3 years ago

Um can someone help me with a question? (theres an attachment with the question there)

Mathematics

1 answer:

Ugo [173]3 years ago

4 0

She needs 15 cans of varnish

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Nine workers are hired to weed a field by

Dmitriy789 [7]

Answer:

144

Step-by-step explanation:

12x12=144

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3 years ago

How many rational numbers are between 1 and 6?

gregori [183]

one ans six are infinite

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3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

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3 years ago

What is the axis of symmetry for the function (x)=5x^2+8?

Hunter-Best [27]

Answer:

x = 0

Step-by-step explanation:

There's no horizontal shift.

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3 years ago

Express each percent as a fraction or mixed number in the simplest form. 2.5%

Blizzard [7]

Answer:

The answer is 2 1/2 or in mixed form 5/2

Hope I helped :)

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3 years ago

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