I need help with this math problem

vichka [17]

Example ProblemsFind the value of "x": 5x = 25. Step 1 : The product is 25 and the given divisor is 5 . Given 5x = 25 . Divide by 5 on both the sides. 5 x 5 = 25 5 . ...Find the value of "x" : 7x = 56; Step 1 : The product is 56 and the given divisor is 7. Given 7x = 56 . Divide by 7 on both the sides. 7 x 7 = 56 7 .

7 0

2 years ago

All tubes of watercolor paint at an art supply store have the the same price. An artist has a coupon for $0.50 off each tube of

BlackZzzverrR [31]

Let us assume the regular price of each tube of paint = r.

0.50 off each tube.

New price of each tube = r - 0.50.

She buy 6 tubes.

Total price of 6 tubes = 6×(r-0.50).

We are given total price = $84.30 .

Therefore, we can setup an equation

6×(r-0.50) = 84.30.

Distributing 6 over (r-0.50), we get

6r - 3.0 = 84.30

Adding 3.0 on both sides, we get

6r - 3.0+3.0 = 84.30+3.0

6r = 87.30

Dividing both sides by 6, we get

6r/6 = 87.30/6

r = 14.55

<h3>Therefore, required equation is 6(r-0.50) = 84.30 and the regular price of each tube of paint is $14.55.</h3>

5 0

2 years ago

There are seven balls in a bag(red, orange, green, yellow, white, black, and purple. If you draw a ball and flip a coin, the cha

Alex17521 [72]

The chance of purple is 14% and the chance of tails is 50%.

please give me brainliest answer :)

4 0

3 years ago

-4/4- (-8/4) Write answer as a decimal

olga_2 [115]

-4/4 can be reduced to -2.
(-8/4) can be reduced to -1.
What you have to do next is to add -1-(-2).
The final answer is 1.
Hope that helps!!!.

8 0

2 years ago

In 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alc

Fynjy0 [20]

Answer:

We conclude that the proportion of adults who totally abstain from alcohol has changed.

Step-by-step explanation:

We are given that in 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?"

Of the 1100 adults surveyed, 429 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and 352 in

Let p = proportion of adults who totally abstain from alcohol.

where, p = $\frac{429}{1100}$ = 0.39

So, Null Hypothesis, $H_0$ : p = 39% {means that the proportion of adults who totally abstain from alcohol has not changed}

Alternate Hypothesis, $H_A$ : p $\neq$ 39% {means that the proportion of adults who totally abstain from alcohol has changed}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who totally abstain from alcohol = $\frac{352}{1100}$ = 0.32

n = sample of adults surveyed = 1100

So, test statistics = $\frac{0.32-0.39}{\sqrt{\frac{0.32(1-0.32)}{1100} } }$

= -4.976

The value of z test statistics is -4.976.

Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the proportion of adults who totally abstain from alcohol has changed.

4 0

2 years ago