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Mrrafil [7]
2 years ago
6

A relay race is 1/4 miles long. There are 4 team members that have to run it. If each team member runs the same distance how man

y miles will each person run?
Mathematics
2 answers:
vova2212 [387]2 years ago
6 0

Answer:

1/4 mile

Step-by-step explanation:

iren2701 [21]2 years ago
3 0

Answer:

1/16 miles

Step-by-step explanation:

1/4 ÷ 4 = 1/16

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if Mark wants to see how the price of gas has increased over the last five years, which type of graph would best illustrate this
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Line graph because it shows differences

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3 years ago
Solve x^2+2x+7=0 using the quadratic formula.
Aneli [31]

Answer:

x=-1\pm \sqrt{6}i

Step-by-step explanation:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(2)\pm\sqrt{2^2-4(1)(7)}}{2(1)}

x=\frac{-2\pm\sqrt{4-28}}{2}

x=\frac{-2\pm\sqrt{-24}}{2}

x=\frac{-2\pm\sqrt{-1*24}}{2}

x=\frac{-2\pm\sqrt{-1}\sqrt{24}}{2}

x=\frac{-2\pm i\sqrt{4*6}}{2}

x=\frac{-2\pm i\sqrt{4}\sqrt{6}}{2}

x=\frac{-2\pm2i\sqrt{6}}{2}

x=-1\pm \sqrt{6}i

5 0
2 years ago
Solve for x.<br><br> -3x+x=2(x-3)
Nat2105 [25]

Answer:

x=-\frac{3}{2}

Step-by-step explanation:

-3x+x=2(x-3)\\ \Leftrightarrow -2x=2x-6\\ \Leftrightarrow 4x=-6\\ \Leftrightarrow x=-\frac{3}{2}

5 0
3 years ago
Read 2 more answers
What shape will the vertical cross-section of<br> a cube be?
andreyandreev [35.5K]

Answer:

a triangle;

Three faces of the cube meet to form the vertex, so the cross section is a two-dimensional figure with three sides

Step-by-step explanation:

3 0
2 years ago
S= 2bh+2bw+2hw solve for w
djverab [1.8K]

Solution, solve\:for\:w,\:s=2bh+2bw+2hw\quad :\quad w=\frac{s-2bh}{2\left(b+h\right)};\quad \:2\left(b+h\right)\ne \:0

Steps:

s=2bh+2bw+2hw

\mathrm{Switch\:sides},\\2bh+2bw+2hw=s

\mathrm{Subtract\:}2bh\mathrm{\:from\:both\:sides},\\2bh+2bw+2hw-2bh=s-2bh

Simplify,\\2bw+2hw=s-2bh

\mathrm{Factor}\:2bw+2hw,\\\mathrm{Rewrite\:as},\\2bw+2hw,\\\mathrm{Factor\:out\:common\:term\:}2w,\\2w\left(b+h\right),\\2w\left(b+h\right)=s-2bh

\mathrm{Divide\:both\:sides\:by\:}2\left(b+h\right);\quad \:2\left(b+h\right)\ne \:0,\\\frac{2w\left(b+h\right)}{2\left(b+h\right)}=\frac{s}{2\left(b+h\right)}-\frac{2bh}{2\left(b+h\right)};\quad \:2\left(b+h\right)\ne \:0

\mathrm{Simplify},\\w=\frac{s-2bh}{2\left(b+h\right)};\quad \:2\left(b+h\right)\ne \:0

\mathrm{The\:Correct\:Answer\:is\:w=\frac{s-2bh}{2\left(b+h\right)};\quad \:2\left(b+h\right)\ne \:0}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

3 0
3 years ago
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