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3 years ago

DO NOT SCROLL PASS!!!! PLEASE HELP AND EXPLAIN SO I CAN GET A UNDERSTANDING.

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

0.06= 6/100

.4 = 4/10

0.006= 6/1000

0.31= 31/100

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Translate each sentence into a formula

Bas_tet [7]

1) Perimeter=2length+2width
This is the formula for finding the perimeter of a rectangle

2) Density=mass/volume
The “Quotient” is the answer to a division problem (like how the “sum” is the answer to an addition problem) which is why we know to divide mass and volume

3) Force = mass*acceleration
The “product” is the answer to a multiplication problem which is why we know to multiply mass and acceleration

4) surface area = 6*L^2
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Hope this helps!

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3 years ago

On a prepaid plan, phone company A charges $76.00 for 500 minutes, and phone

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Answer:

Company B

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A is $0.15/min

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because 54/450

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3 years ago

On a number line ,1.42 would be located.choose all answer that make a true statement

IgorC [24]

Answer: A, D

Explanation:

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2 years ago

Roasted peanuts cost 3 per pound at the local market. What is the cost of a 6 pound bag of peanuts

Novosadov [1.4K]

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3 years ago

Read 2 more answers

Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f

GalinKa [24]

Answer:

$\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }$

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

$\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}$

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

$f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240$

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in $\mathbb{R}$ .

$\\f(x)=(x^2+16)(x^2-2x-15)$

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

$f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}$

And we can write in $\mathbb{C}$

$f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0

3 years ago