Y= a(x-3)^2+6
2= a(0-3)^2+6
2=a(-3)^2+6
2=a(9)+6
2-6=9a
-4=9a
-4/9=a
Therefore the equation in vertex form is
y = -4/9 (x-3)^2+6
Answer:
42, 138, and 138 degrees DON'T FORGET THE DEGREES SIGNS!!!!!
Step-by-step explanation:
Using vertical angles theorem, we can get another 42, 180-42, and 180-42.
So we have 42, 138, and 138
Answer:
Total Distance = 2 miles
Step-by-step explanation:
We know D = RT where
D is distance
R is rate (speed)
T is time
First Leg:
Rate = x mph
Time = 20/60 = 1/3 hour
Hence, D = RT, Distance = x * 1/3 = x/3 miles
Second Leg:
Rate = x - 1
Time = 30/60 = 1/2 hour
Distance = (x - 1) * 1/2 = (x-1)/2
Total distance is the sum of both the legs, hence,
Total distance =
miles
Since both the distance are equal we can equate and solve:

Plugging this x = 3 into the total distance expression, we get:

Total distance, 2 miles
Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation =
= 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:

For z = -1.56, we get:

For z = -0.88, we get:

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
What are you supposed to be doing