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SIZIF [17.4K]
3 years ago
8

Anybody know the anwser

Mathematics
1 answer:
Darya [45]3 years ago
3 0

Answer:

A 3 goes in the parentheses. The expression evaluates to 59.

Step-by-step explanation:

b = 3

2b^3 + 5 =

= 2(3)^3 + 5

= 2 * (3 * 3 * 3) + 5

= 2 * 27 + 5

= 54 + 5

= 59

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Answer: 3/11 = 0.27272727272727, -5/8 =  0.625

Step-by-step explanation:

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Answer:

7

Step-by-step explanation:

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Is this a relation or a function explain your answer
mash [69]
Relation because a function can not have two ( , ) with the same x value.
4 0
3 years ago
PLEASE HELP!!!!!!!
andre [41]

Answer:

\frac{4^{21}}{5^6}

Step-by-step explanation:

\left(\frac{4^7}{5^2}\right)^3

=\frac{\left(4^7\right)^3}{\left(5^2\right)^3}

\left(4^7\right)^3

=4^{21}

=\frac{4^{21}}{\left(5^2\right)^3}

\left(5^2\right)^3

5^6

=\frac{4^{21}}{5^6}

6 0
3 years ago
Find f(a), f(a+h), and<br> 71. f(x) = 7x - 3<br> f(a+h)-f(a)<br> h<br> if h = 0.<br> 72. f(x) = 5x²
Leni [432]

Answer:

71. \ \ \ f(a) \  = \  7a \ - \ 3; \ f(a+h) \  =  \ 7a \ + \ 7h \ - \ 3; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 7

72. \ \ \ f(a) \  = \  5a^{2}; \ f(a+h) \  =  \ {5a}^{2} \ + \ 10ah \ + \ {5h}^{2}; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 10a \ + \ 5h

Step-by-step explanation:

In single-variable calculus, the difference quotient is the expression

                                              \displaystyle\frac{f(x+h) \ - \ f(x)}{h},

which its name comes from the fact that it is the quotient of the difference of the evaluated values of the function by the difference of its corresponding input values (as shown in the figure below).

This expression looks similar to the method of evaluating the slope of a line. Indeed, the difference quotient provides the slope of a secant line (in blue) that passes through two coordinate points on a curve.

                                             m \ \ = \ \ \displaystyle\frac{\Delta y}{\Delta x} \ \ = \ \ \displaystyle\frac{rise}{run}.

Similarly, the difference quotient is a measure of the average rate of change of the function over an interval. When the limit of the difference quotient is taken as <em>h</em> approaches 0 gives the instantaneous rate of change (rate of change in an instant) or the derivative of the function.

Therefore,

              71. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{(7a \ + \ 7h \ - \ 3) \ - \ (7a \ - \ 3)}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{7h}{h} \\ \\ \-\hspace{4.25cm} = \ \ 7

               72. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{{5(a \ + \ h)}^{2} \ - \ {5(a)}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{{5a}^{2} \ + \ 10ah \ + \ {5h}^{2} \ - \ {5a}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{h(10a \ + \ 5h)}{h} \\ \\ \-\hspace{4.25cm} = \ \ 10a \ + \ 5h

4 0
2 years ago
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