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ludmilkaskok [199]
3 years ago
14

What are thex intercepts of 푓(푥) = − 1 5 푥 4 −푥 3 +푥 2 +7푥 +7

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

Is this language Chinese

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Translate the verbal phrase to an equation, Two eighths of a number minus 4 is 2.
erastovalidia [21]

Answer:

2/8(x) - 4 = 2

<em>Hope this helps! </em>

8 0
3 years ago
You mow the lawn to earn your allowance. Each time you mow the lawn you earn $12. Write an equation for the number of dollars, d
lidiya [134]
It would simply be d(m)
5 0
4 years ago
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The equation R=10a-20 represents the revenue R (in dollars) you make by spending A dollars on advertising. You revenue totaled $
timurjin [86]
R = 10a - 20
ur revenue totaled 110...so R = 110

110 = 10a - 20
110 + 20 = 10a
130 = 10a
130/10 = a
13 = a <== so u spent $13 on advertising
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3 years ago
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A random sample of 85 sixth-graders in a large city take a course designed to improve scores on a reading comprehension test. Ba
BartSMP [9]

Answer:

12.6 < \mu < 14.8

For this case we can find the margin of error like this:

ME= \frac{14.8-12.6}{2}= 1.1

Since we need to divide the width of the interval by 2.

And now with the margin of error we can find the sample mean with any of the two following ways:

12.6 +1.1=13.7

14.8-1.1=13.7

So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=85-1=84

We know that the confidence interval is given by:

12.6 < \mu < 14.8

For this case we can find the margin of error like this:

ME= \frac{14.8-12.6}{2}= 1.1

Since we need to divide the width of the interval by 2.

And now with the margin of error we can find the sample mean with any of the two following ways:

12.6 +1.1=13.7

14.8-1.1=13.7

So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

3 0
3 years ago
I need help please and thank you
ExtremeBDS [4]

Answer:

D=340

Step-by-step explanation:

360-180/9

360-20

340

4 0
4 years ago
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