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lapo4ka [179]
3 years ago
10

According to the table, which ordered pair is a local maximum of the function, f(x)? (0, 64) (3, –35) (5, 189) (2, 0)​

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
(0, 64) is the right answer
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Us
dsp73

Answer:

{ \sf{y = x + { \green{[ \:  \: ]}}}}

• when y is 0, x is 5

{ \sf{0 = 5 + { \green{[ \:  \: ]}}}} \\  \\ { \sf{ \green{[ \:  \: ]}} =  - 5}

• therefore relationship is:

{ \boxed{ \sf{y =  x - 5}}}

6 0
3 years ago
Read 2 more answers
I need help pls and explainnnnn
torisob [31]
Answer: 5.2cm^3

Steps:
Volume of a cylinder- V = π * r^2 * h
146.952 = π * 3^2 * h
146.925 = π * 9 *h
146.925 = 28.2743338823 * h
146.925 / 28.2743338823 = h

5.19640889201 = h
5.2 = h
7 0
3 years ago
Given f(x)=6x+9 and g(x)=x^4, choose the expression for (f*g) (x)
egoroff_w [7]
(f*g)(x) means multiply the rules of each function.
(f*g)(x) = (6x + 9) × x^{4}

             = 6x( x^{4} )+9( x^{4} ) ← Distributive property
             
             = 6 x^{5} +9 x^{4}  ← remember add exponents on like base when multiplying

ANSWER: 6 x^{5} +9 x^{4} 

8 0
4 years ago
Find the inverse function of
Neko [114]

The correct answer is C. m-1(x) = \frac{x + 5}{5}


You can find the value of any inverse function by switching the m(x) and the x value. Then you can solve for the new m(x) value. The end result will be your new inverse function. The step-by-step process is below.


m(x) = 5x - 5 ----> Switch m(x) and x

x = 5m(x) - 5 ----> Add 5 to both sides

x + 5 = 5m(x) ----> Divide both sides by 5

\frac{x + 5}{5} = m(x) ----> Change the order for formatting purposes.

m(x) = \frac{x + 5}{5}


And this would be your inverse, which matches answer C.



5 0
3 years ago
Someone help me out. I dont know how to do this
Fittoniya [83]

Answer:

\huge\boxed{r_{x-axis}(x,\ y)\to(x,\ -y)}

Step-by-step explanation:

Read the coordinates of the points:

A(-1, 0) → A'(-1, 0)

B(0, 2) → B'(0, -2)

C(3, 2) → C'(3, -2)

D(4, 0) → D'(4, 0)

(x, y) → (x, -y)

Check:

A → A': (-1, 0) → (-1, -0) = (-1, 0)    CORRECT

B → B': (0, 2) → (0, -2)      CORRECT

C → C': (3, 2) → (3, -2)        CORRECT

D → D': (4, 0) → (4, -0) = (4, 0)     CORRECT

4 0
3 years ago
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