Step-by-step explanation:
p² + q² + 5(p² + q²)
= 1(p² + q²) + 5(p² + q²)
= (1 + 5)(p² + q²)
= 6(p² + q²).
Answer:
<em>Multiply the bottom equation by -3/2 then add the equations.
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<em>Multiply the top equation by-3. then add the equations
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Step-by-step explanation:
Given the simultaneous equation
2x- 6y=6 ... 1
6x - 4y = 2 ... 2
To eliminate a variable, we have to make the coefficient of one of the variable to be the same.
Multiply equastion 1 by -3
-6x+18y= -18
6x - 4y = 2
Add the result:
-6x + 6x + 18y-4y = -18+2
18y-4y = -18+2
14y = -18
y = -9/7
Another way is to Multiply the bottom equation by -3/2 then add the equations.
Multiplying equation 2 by -3/2 will give;
6x(-3/2) - 4y(-3/2) = 2(-3/2)
-9x + 6y = -3
Add to equation 1;
2x- 6y=6
-9x + 2x + 0 = -3+6
-7x = 3
x = -3/7
Hence the correct two options are;
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
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</em>
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The answer is D.
Factor the equation (what factors of -72 add up to 34)
(x + 36)(x - 2) = 0
x = -36, x = 2
