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andrew-mc [135]
3 years ago
10

Which is true about the solution to the system of inequalities shown

Mathematics
2 answers:
rosijanka [135]3 years ago
7 0
Pls provide the problem
Rainbow [258]3 years ago
5 0

Answer:

look below for question

Step-by-step explanation:

Which is true about the solution to the system of inequalities shown?

y > 3x + 1

y < 3x – 3  

Only values that satisfy y > 3x + 1 are solutions.

Only values that satisfy y < 3x – 3 are solutions.

Values that satisfy either y > 3x + 1 or y < 3x – 3  are solutions.

There are no solutions.

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Oduvanchick [21]
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8 0
3 years ago
Esmeralda received a bag of jellybeans that contained a mixture of regular flavored jellybeans and "surprise" jellybeans. The ba
Firlakuza [10]

Answer:

6  "surprise" flavors jellybeans

Step-by-step explanation:

From the information given:

The bag contained a mixture of regular flavored jellybeans and "surprise" jellybeans.

There are 40 jellybeans in the bag.

If 15% of the jellybean were "surprise" flavors.

Then, the number of expected "surprise" jellybeans will be:

= 15% of 40 jellybeans

= (15/100) × 40

= 6  "surprise" flavors jellybeans

If  6 surprise jellybean is contained in the bag;

Thus, the number of regular flavored jellybean will be

= 40 - 6

= 34 regular flavored jellybean

5 0
3 years ago
A ball is thrown into the air from the roof of a building that is 25
guapka [62]

See https://web2.0calc.com/questions/help_29603.

6 0
4 years ago
Every positive real number has a positive and a negative square root, the ________ root is called the principal root. *
fomenos

9514 1404 393

Answer:

  B) positive

Step-by-step explanation:

For even-index roots, which may be either positive or negative, the <u> </u><u><em>positive</em></u><u> </u> root is called the principal root.

5 0
3 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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