To determine which relation is a function, we can perform something called the vertical line test. We cover the graph in repeating vertical lines and if one vertical line connects with more than one point of the relation, the relation is not a function.
The relation in the bottom right corner is the only relation that passes the vertical line test.
Answer:
no is not fully correct for the name part you need to put the names of the elements in the compound
Step-by-step explanation:
I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
Answer:
D) 
Step-by-step explanation:
If two functions 
and 
are inverse of each other, then the following conditions must be true:
i. 
ii.
Therefore, out of the four choices available, only option D matches the condition for inverse function to exist.
Therefore,
