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Hunter-Best [27]
3 years ago
12

A red kangaroo jumps along 40 km/h. At this rate how long would it take to jump 2 km

Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0
It is 20 mile per hour
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Can I Get A Little Help Here?
Musya8 [376]
Hey there :)

We know the formula for simple interest is 
I = prt
{ The picture includes what each stands for }

Lehena:
Initial amount = $100
Interest rate = 2.5% = \frac{2.5}{100} = 0.025
Time = 3 years
I = ( 100 )( 0.025 )( 3 )
  = 7.5$

Total = $100 + $7.5 = $107.5

Marty:
Initial amount = $100
Interest rate = 2% = \frac{2}{100} = 0.02
Time = 3 years
I = ( 100 )( 0.02 )( 3 ) 
  = $6

Total = $100 + $6 = $106

How much more than Marty did Lehena receive?
= Total Amount of Lehena - Total Amount of Marty
= 107.5 - 106
= $1.5

Your answer will be option B) $1.50

7 0
3 years ago
Divide x to the 1 half power divided by x to the 2 sevenths power.
juin [17]

\frac{x^\frac{1}{2} }{x^\frac{2}{7}}

According to the rule of exponents \frac{a^m}{a^n} = a^{(m-n)} , i.e. when two terms are in division with same base , we subtract the exponents

So

\frac{x^\frac{1}{2} }{x^\frac{2}{7}} = x^{(\frac{1}{2}) - (\frac{2}{7})}

=x^\frac{3}{14}

Or

x to the 3 fourteenths power

5 0
3 years ago
For questions 8 – 10, answer the questions about tangent-tangent angles.
olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

                                                   = \frac{1}{2}(220-140)

                                                   = \frac{1}{2}(80)

                                                   = 40°

9). Following the same rule as above,

Angle formed between two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

125 = \frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]

250 = [m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = \frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])

                          = \frac{1}{2}(254-106)

                          = \frac{148}{2}

                          = 74°

4 0
2 years ago
The perimeter of a rectangle is 50 centimeters. If the width of the rectangle is 9 centimeters
nordsb [41]

Answer:

Length = 17 cm

Width = 8 cm

Step-by-step explanation:

Let the length be x cm

Therefore, Width = (x - 9) cm

Perimeter of rectangle = 2(l +w)

50 = 2[x + (x - 9)]

50/2 = 2x - 9

25 = 2x - 9

25+ 9 = 2x

2x = 34

x = 34/2

x = 17 cm

x - 9 = 17 - 9 = 8 cm

Therefore,

Length = 17 cm

Width = 8 cm

Thus, the dimensions of the rectangle are 17 cm and 8 cm.

6 0
2 years ago
a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle
madam [21]

Answer:

A.

H_0: \mu\leq514\\\\H_1: \mu>514

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

<em>A. state the null and alternative hypotheses.</em>

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

H_0: \mu\leq514\\\\H_1: \mu>514

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C.​ do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

8 0
3 years ago
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