Answer:
i belive it is 1,3,4,5
Step-by-step explanation:
To do this, complete the square:
p(x) = 21 + 24x + 6x2 => <span>p(x) = 6x2 + 24x + 21
Rewrite the first 2 terms as
6(x^2 + 4x)
then you have </span><span>p(x) = 6(x2 + 4x ) + 21
Now complete the square of x^2 + 4x:
p(x) = 6(x^2 + 4x + 4 - 4) + 21
= 6(x+2)^2 - 24 + 21
p(x) = 6(x+2)^2 - 3 this is in vertex form now.
We can read off the coordinates of the vertex from this: (-2, -3)</span>
You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation
... 3v + 7c = 4480
In intercept form, this equation is
... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480
Among other things, this tells us one solution is
... (v, c) = (0, 640)
The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.
The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)
We can also pick some number in between, say using 100 as the multiple
... (0 +100·7, 640 -100·3) = (700, 340)
In summary, your three solutions could be
... (visors, caps) = (0, 640), (700, 340), (1491, 1)
Length of arc = (15/360) * 2*3.14*20 = 5.23 ins
circumference of the circle = 2*3.14*24 = 150.72
angle at center from 10 ft arc = (10/150.72) * 360 = 23.89 degrees
A translation is a rigid transformation, which means angle measures and distances from two points do not change.
Polygon ABCDEF is congruent to polygon A'B'C'D'E'F'
DE = D'E' = 7
