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Tema [17]
3 years ago
7

If there are 160 calories in 8 ounces of milk then, how many calories are there in a 15 ounce cup of milk.

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0
300, because 8x20=160 so 1 ounces= 20 calories
15x20=300
Karolina [17]3 years ago
6 0
Answer is 300 because if u divide 160 and 80 the answer is 20, so u need to multiple 20 times 15 and the answer gonna be 300
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The length of each stair is 11 inches.what is the rise, r for each stair? Round to the nearest.
Keith_Richards [23]
Is that the entire question? There has to be more information.
7 0
4 years ago
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Roberta works in a home appliance store. She is paid $195 per week and 3% on all sales over $1,000. During one year, her average
Ymorist [56]

Answer:

300,750

Step-by-step explanation:

8 0
3 years ago
PLEASE I NEED HELP WITH BOTTOM PART WILL MARK BRAINLIEST!!
kipiarov [429]

Answer:

13.

parallel: y = 1/3x -3

perpendicular: y = -3x - 3

14.

parallel: y = 4x - 1/2

perpendicular: y = -1/4x - 1/2

15.

parallel: y = -2x + 4

perpendicular: y= 1/2x + 4

16.

parallel: y = -2x-2

perpendicular: y= 1/2x-2

17.

parallel: y = -2x+8

perpendicular: y= 1/2x + 8

Step-by-step explanation:

A perpendicular has a negative reciprocal slope and a parallel has the same slope

6 0
3 years ago
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Me ajudem por favor<br><br><br><br><br> PS: Explicar resposta
PolarNik [594]

Answer:

B

Step-by-step explanation:

√16/25 = 4/5 = 0.8-> (4/5 x 4/5 = 16/25)

(2/5)^3 = 8/125  = 0.064

-(-0.3)^3 = 0.027 (an odd exponent mantains the same sign of the number and minus x minus = +)

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-13 is a negative number so it is surely the smallest

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8 is major than 0, so 0.8 is the greatest number

we have

-√169 ; -(-0.3)^3 ; (2/5)^3 ; √16/25

4 0
3 years ago
What is the slope-intercept form of linear equations?
lara31 [8.8K]

to get the equation of any straight line, we simply need two points off of it, let's use the points from the picture below.

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\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{8}) \\\\\\ y-3=\cfrac{1}{2}x-4\implies y=\cfrac{1}{2}x-1

if we already have the slope, and we can see the y-intercept on the table, then we can simply use the slopel-intercept form and plug both of them in.

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \begin{array}{|c|ll} \cline{1-1} slope\\ \cline{1-1} \cfrac{1}{2}\\ \cline{1-1} y-intercept&\\\cline{1-1} (0~~,~~-1)\\ \cline{1-1} \end{array}~\hfill y=\cfrac{1}{2}x-1

6 0
2 years ago
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