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3 years ago

Hello who here is good at math i need help

Mathematics

1 answer:

maria [59]3 years ago

3 0

Answer:

sup

Step-by-step explanation:

whats your question

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Number two is thirty weeks

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4 years ago

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3 years ago

Read 2 more answers

Given the system of constraints name all vertices. Then find the maximum value of the given objective

larisa86 [58]

Answer:

$35$

Step-by-step explanation:

The constraints are

The red line represents the function

$y\leq \dfrac{1}{3}x+1$

At $y=0$

$0=\dfrac{1}{3}x+1\\\Rightarrow -1=\dfrac{1}{3}x\\\Rightarrow x=-3$

At $x=0$

$y=0+1\\\Rightarrow y=1$

Two points are $(-3,0),(0,1)$

The blue line represents the function

$5\geq y+x$

at $y=0$

$5=x$

at $x=0$

$y=5$

Two points are $(5,0),(0,5)$

The other two constraints are $x\geq 0$ , $y\geq 0$ . So, the point has to be in the first quadrant

From the graph it can be seen there are two points where the function will be maximum let us check them.

$(3,2)$

$7x-2y=7\times 3-2\times 2=17$

$(5,0)$

$7x-2y=7\times 5-2\times 0=35$

So, the maximum value of the function is $35$ .

3 0

3 years ago

What is the quotient of 13divide 8

Ahat [919]

Answer:

Step-by-step explanation:

mr clean

7 0

2 years ago

Read 2 more answers

Factor completely 81x8 − 1. (9x4 − 1)(9x4 1) (3x2 − 1)(3x2 1)(9x4 − 1) (3x2 − 1)(3x2 1)(9x4 1) (3x2 − 1)(3x2 1)(3x2 1)(3x2 1).

mojhsa [17]

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Step-by-step explanation:

Using the identity for the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b)

we put a^2 = 81x^8 and b^2 = 1 giving

a = 9x^4 and b = 1, so:

81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)

Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

4 0

2 years ago