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spin [16.1K]
3 years ago
8

Solve 28 - K _> 7(K - 4)

Mathematics
1 answer:
Evgen [1.6K]3 years ago
7 0

Answer:

Solving the inequality 28-K\geq 7(K-4), we get \mathbf{K\leq 7}

Step-by-step explanation:

We need to solve the inequality 28-K\geq 7(K-4)

Using the BODMAS rule, first we will solve the bracket:

28-K\geq 7(K-4)\\28-K\geq 7K-28

Now, we will subtract 28 from both sides

28-K-28\geq 7K-28-28\\-K\geq 7K-56

Subtracting -7k on both sides

-K-7K\geq 7K-56-7K\\-8k\geq -56

Finally, divide both sides by -8 and inverse the inequality, as we are dividing with a minus digit.

\frac{-8K}{-8}\leq \frac{-56}{-8}\\K\leq 7

So, solving the inequality 28-K\geq 7(K-4) we get \mathbf{K\leq 7}

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