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Damm [24]
3 years ago
9

Whats 10m +1890324cm

Mathematics
2 answers:
zhuklara [117]3 years ago
6 0

Answer:

18 913.24m

Step-by Step Results

(10 meters) + (1 890 324 centimeters) =

18 913.24

eimsori [14]3 years ago
5 0

Answer:

18913.24

Step-by-step explanation:

1 cm = 0.01 m.

To convert it, multiply 1890324 by 0.01,

You get 18903.24

Then you add the final 10 m and get 18913.24

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A town has a population of 19000 and grows at 4.5% every year. To the nearest tenth of a year, how long will it be until the pop
steposvetlana [31]

Answer:

If the population grows by 4% each year then

the population in any given year is 104% of

the previous year or 1.04 times as much

P(t) = P0(1.04)t

P(t) is population at time t years

P0 = initial population = 11,000

t = number of years = 15

P(15) = 11,000(1.04)15

P(15) = 19,810 people

Step-by-step explanation:

3 0
3 years ago
A. Is this an arithmetic sequence? How do you know?
pogonyaev

Answer:

a. Yes. The difference is common and equal to $1750

b. $1750

c. $20000 was initial investment

d. This is linear equation with start point of 20000 and slope of 1750:

  • y = 1750x + 20000

e. After another 10 years (on the top of 5 given) the investment will be:

  • y = 1750*15 + 20000 = $46250

f. After 20 years the value of investment will be:

  • y = 1750*20 + 20000 = $55000
7 0
3 years ago
All movies in a store are being discounted 30%. Let x represent the regular price of a
bagirrra123 [75]
D bc the price is 30 %
4 0
3 years ago
Write an expression to match the description: 2 less than y
AveGali [126]
<h3>Answer:</h3>

y - 2

<h3>Step-by-step explanation:</h3>

You get 2 less than a value when you subtract 2 from that value.

3 0
3 years ago
Fifteen years ago, you deposited $12,500 into an investment fund. Five years ago, you added an
True [87]

Answer:

a) 8.16%

b) $65,762.50

c) $39,701.07

Step-by-step explanation:

Given:

15 years ago, Initial investment = $12500

5 years ago, Investment = $20000

Nominal interest = 8% semi annually for first 10 years

Interest2= 6.5% compunded annually for last five years

a) for the effective annual interest rate (EAR) in the first 10 years, let's use the formula:

[1+(nominal interest rate/number of compounding periods)]^ number of compounding periods-1

EAR = [1 + (\frac{0.08}{2})]^2 - 1

= (1 + 0.04)^2 - 1

= (1.04)^2 - 1

= 1.0816 - 1

= 0.0816

= 8.16%

The effective annual interesting rate, EAR = 8.16 %

b) To find the amount in my account today.

Let's first find the amount for $12500 for 10 years compounded semi annually

= 12,500 +( 12,500 * 8.160% * 10)

= $ 22,700

Let's also find the amount for $32,500($12,500+$20,000) for 5 Years compoundeed annually

$32,500 + ($32,500 * 6.5% *5)

= $ 43,062.50

Money in account today will be:

$22,700 + $43,062.50

= $65,762.50

c) Let's the amount I should have invested to be X

For first 10 years at 8.160%, we have:

Interest Amount = ( X * 8.160% * 10 ) = 0.8160 X

For next 5 years at 6.5%, we have:

Interest Amount = (X * 6.5% * 5) = 0.325 X

Therefore the total money at the end of 15 Years = 85000

0.8160X + 0.3250X + X = $85,000

= 2.141X = $85,000

X = 85,000/2.141

X = 39,701.074 ≈ $39,700

If I wish to have $85,000 now, I should have invested $39,700 15 years ago

7 0
3 years ago
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