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nikdorinn [45]
3 years ago
11

Intel estimates that about 12 quintillion transistors are shipped around the globe each year. If that represents 10,000 times th

e number of ants on the planet, find the number of ants on Earth. (Show all your workings. Final answer MUST standard notation.)
Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

Number on ants on Earth = 1.2 × 10¹⁵

Step-by-step explanation:

1 quintillion = 10¹⁸ or (1000000000000000000)

∴ 12 quintillion = 12 × 10¹⁸

12 quintillion = 10,000 × Number of ants on Earth

Let the number of ants on Earth = n

12 quintillion = 10,000 × n

dividing both sides by 10,000

12 quintillion ÷ 10,000 = n

n = \frac{12\ \times\ 10^{18} }{10,000} \\n =  \frac{12\ \times\ 10^{18} }{10^{4}}\\n = 12\ \times\ \frac{10^{18}}{10^{4}} \\applying\ the\ second\ law\ of\ indices\ (\frac{x^m}{x^n} = x ^{m-n})\\ n = 12\ \times\ 10^{(18 - 4)\\n = 12\ \times 10^{14}\\in\ standard\ form\\n = 1.2\ \times 10\ \times\ 10^{14}\\\therefore n = 1.2\ \times\ 10^{15}

Number on ants on Earth = 1.2 × 10¹⁵

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Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180
torisob [31]

I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

.

{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

25 =  {y}^{2}

y = 5

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

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( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

-  \frac{63}{65}

Hope this helps

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Darnel decided to make his grandmother's favorite pound cake. In the recipe, it calls for 2 cups of sugar but Darnel added 3 cup
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Percent Error Formula =

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