Find the difference per row:
10 seats in the first row
30 seats in the sixth row:
30 -10 = 20 seats difference.
6-1 = 5 rows difference.
20 seats / 5 rows = 4 seats per row.
This means for every additional row, there are 4 more seats per row.
The equation would be:
Sn = S +(n-1)*d
Where d is the difference = 4
S = number of seats from starting row = 10
n = the number of rows wanted
S(11) = 10 + (11-1)*4
S(11) = 10 + 10*4
S(11) = 10 + 40
S(11) = 50
Check:
Row 6 = 30 seats
Row 7 = 30 + 4 = 34 seats
Row 8 = 34 + 4 = 38 seats
Row 9 = 38 + 4 = 42 seats
Row 10 = 42 + 4 = 46 seats
Row 11 = 46 + 4 = 50 seats.
Answer:
-5
Step-by-step explanation:
Answer:
x1=-4 x2=2
Step-by-step explanation:
Answer:
x = 6.5cm
Step-by-step explanation
Assuming that you know the abbreviation SOH CAH TOA, you can solve this easily
What we need to find is x, which is the adjacent (A) side. The other value given is the hypotenuse (H), 13cm. We will see that given A and H, we can use cosine .
cos(60) = x / 13 (remember: cos(angle) = A / H)
Multiply 13 to the other side to get x by itself,
13cos(60) = x
x = 13cos(60)
= 6.5
Hope this helps!
