Answer:
BPEMDAS (brackets, parentheses, exponents, multiplication and division, addition and subtraction)- Left to right
Notes: Two negatives make a positive. When you have an odd exponent of an negative number, you get a negactive result.
2-(-8)+(-2)³
10-8
2
Hope this makes sense! :)
Answer:
-1
Step-by-step explanation:
The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.
d(log(x))/dx = 1/(x·ln(10))
d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))
Then the ratio of these derivatives is ...
lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x
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At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.
d(-sin(x)cos(x))/dx = -cos(2x)
dx/dx = 1
so the limit is ...
lim = -cos(2x)/1
lim = -1 when evaluated at x=0.
_____
I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.
Years = Natural Logarithm(Total / Principal) / rate
Years = ln (1,200 / 1,000) / .06
Years = ln (6 / 5) / .06
Years = ln (1.2) / .06
Years = 0.18232155679 / .06
Years =
<span>
<span>
<span>
3.0386926132
</span>
</span>
</span>
Years =
<span>
<span>
<span>
3.0 (rounded)
</span></span></span>answer is B
Answer:

Step-by-step explanation:
We can write the following system of equations:
Let the first number be
and the second number be
:

Solving, we get:

Solving for
:
