Answer:
The midpoint of the points (2,8) and (0,4) is given by:
(
2
x
1
+x
2
,
2
y
1
+y
2
)=(
2
2+0
,
2
8+4
)=(
2
2
,
2
12
)=(1,6)
We must must transform the standard form equation −3x+6y=5 into a slope-intercept form equation (y=mx+b) to find its slope.
−3x+6y=5 (Subtract 3x on both sides.)
6y=3x+5 (Divide both sides by 6.)
y=
6
3
x+
6
5
y=
2
1
x+
6
5
The slope of our first line is equal to
2
1
. Perpendicular lines have negative reciprocal slopes, so if the slope of one is x, the slope of the other is
x
1
.
The negative reciprocal of
2
1
is equal to −2, therefore, −2 is the slope of our line.
Since the equation of line passing through the midpoint (1,6), therefore, substitute the given point in the equation y=−2x+b:
6=(−2×1)+b
6=−2+b
b=6+2=8
Substitute this value for b in the equation y=−2x+b:
y=−2x+8
Hence, the equation of the line is y=−2x+8.
Step-by-step explanation:
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