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Sauron [17]
3 years ago
12

Which equation represents the relationship shown in the table?

Mathematics
2 answers:
Mila [183]3 years ago
5 0
Y=4x because 20/5 equals 4
zysi [14]3 years ago
4 0

Answer:

The equation  is y = 4x

Step-by-step explanation:

From the table we can pick any 2 points (x_1,y_1) \ \text{ and } \ (x_2, y_2) such, we can obtain the slope of the line given 2 points using the following equation

m  = \cfrac{y_2-y_1}{x_2-x_1}.

Then we can compare  to the given options, or alternatively find the y-intercept using any point of the line, to get a line equation that looks like y = mx+b

Finding the slope.

We can pick the first 2 points, that is (1,4) and (5, 20).

Replacing them on the slope equation give us,

m=\cfrac{20-4}{5-1}

Simplifying we get

m=\cfrac{16}{4}\\m=4

Thus the only option that has slope 4 is the line equation y = 4x which is the right answer for the exercise.

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3 0
3 years ago
Read 2 more answers
What life cycle adaptation allows a seahorse to make lots of babies in a short amount of time? (2 points)
Zielflug [23.3K]

The seahorse make a lot of babies because the male carries the babies while the female makes more eggs.

<h3>What is mating?</h3>

Mating is the process in which opposite or hermaphroditic organisms pair for reproduction.

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Find out more on mating at: brainly.com/question/922533

4 0
2 years ago
It is 10:30pm and my brain is not cooperating with me.
r-ruslan [8.4K]

Answer:

v = 180 {cm}^{3}

Step-by-step explanation:

V= <em>lwh</em><em> </em>or <em>l</em><em> </em><em>*</em><em>w</em><em>*</em><em>h</em>

<em>Length</em><em>:</em><em> </em><em>15</em>

<em>Width</em><em>:</em><em> </em><em>3</em>

<em>Height</em><em>:</em><em>4</em>

<em>V</em><em>=</em><em>15</em><em>*</em><em>3</em><em>*</em><em>4</em>

V=180

5 0
1 year ago
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$375, 319
frutty [35]

Answer:

need a answer

Step-by-step explanation:

7 0
3 years ago
Consider these functions:
Lana71 [14]

Answer:

Answer is 12

Step-by-step explanation:

f(g(-2))

=f((-2)^2+2)

=f(6)

=-1/2×6^2+5×6

=12

7 0
2 years ago
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