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maria [59]
3 years ago
14

Can someone give me the answer please it would mean a lot!

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

It can be written as:

(9m)(9m)(9m)(9m)

Step-by-step explanation:

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Evaluate the following expression when t=5 when t^2-2t-2
Black_prince [1.1K]

Answer:

<h2><u><em>13</em></u></h2>

Step-by-step explanation:

Evaluate the following expression when

t=5 when t^2-2t-2

replace t with 5 and remember PEMDAS

5² - 2 * 5 - 2 =

25 - 10 - 2 =

13

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3 years ago
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when Jimmy gets a rise or work a little more hours then John

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Ipatiy [6.2K]

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Parallelogram, Quadrilateral,Rhombus

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Step-by-step explanation:

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra
Rainbow [258]

Answer:

x = t

y = 1 - t

z = 2t

Step-by-step explanation:

Given

x=t

y=e^{-t}

z=2t-t^2

(0, 1, 0)

The vector equation is given as:

r(t) = (x,y,z)

Substitute values for x, y and z

r(t) = (t,\ e^{-t},\ 2t - t^2)

Differentiate:

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

The parametric value that corresponds to (0, 1, 0) is:

t = 0

Substitute 0 for t in r'(t)

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

r'(0) = (1,\ -e^{-0},\ 2 - 2*0)

r'(0) = (1,\ -1,\ 2 - 0)

r'(0) = (1,\ -1,\ 2)

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

r(t) = a + tv

Such that:

a = (0,1,0) and v = r'(0) = (1,-1,2)

The equation becomes:

r(t) = (0,1,0) + t(1,-1,2)

r(t) = (0,1,0) + (t,-t,2t)

r(t) = (0+t,1-t,0+2t)

r(t) = (t,1-t,2t)

By comparison:

r(t) = (x,y,z) and r(t) = (t,1-t,2t)

The parametric equations for the tangent line are:

x = t

y = 1 - t

z = 2t

7 0
3 years ago
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