we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
The answer should be X = Z / 6piy
Answer:
1/3
Step-by-step explanation:
When working with balanced expressions (stuff on both sides of the equal sign), "what you do to one side, you do to the other", which keeps it balanced.
The first thing we notice is the exponent 1/4, which is one both sides, so we can get rid of it on both sides by using the <u>reverse operation</u>.
The reverse of exponents is <u>square root</u>.
![(4x + 10)^{\frac{1}{4}} = (9 + 7x)^{\frac{1}{4}}\\\sqrt[\frac{1}{4}]{(4x + 10)^{\frac{1}{4}}} = \sqrt[\frac{1}{4}]{(9 + 7x)^{\frac{1}{4}}}\\\\4x + 10 = 9 + 7x](https://tex.z-dn.net/?f=%284x%20%2B%2010%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%3D%20%289%20%2B%207x%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%5Csqrt%5B%5Cfrac%7B1%7D%7B4%7D%5D%7B%284x%20%2B%2010%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%20%3D%20%5Csqrt%5B%5Cfrac%7B1%7D%7B4%7D%5D%7B%289%20%2B%207x%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5C%5C%5C%5C4x%20%2B%2010%20%3D%209%20%2B%207x)
Isolate x to solve. Separate the variables and non-variables.
4x + 10 = 9 + 7x
4x - 4x + 10 = 9 + 7x - 4x Subtract 4x from both sides
10 = 9 + 3x
10 - 9 = 9 - 9 + 3x Subtract 9 from both sides
1 = 3x Divide both sides by 3 to isolate x
x = 1/3 Answer
Answer: D
Step-by-step explanation:
This is a diffficult question was there a chart