Question

Simplify p^-8/7^-2q^-9

Answer 1

Answer:

$\frac{7^2}{p^8 \cdot q^9}$

Step-by-step explanation:

$\frac{p^{-8}}{7^{-2}} \cdot q^{-9} = \frac{\frac{1}{p^8}}{\frac{1}{7^2}} \cdot \frac{1}{q^9} = \frac{7^2}{p^8 \cdot q^9}$ by the definition of negative exponents: $a^{-b} = \frac{1}{a^b}$ for all $a,b$ so long as $a\ne 0$.