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dolphi86 [110]
2 years ago
10

What is the value of m in this proportion?

Mathematics
2 answers:
Kitty [74]2 years ago
8 0

Answer:

m=108\frac{11}{14}

Explanation:

1523 = 14 m

switch sides:

14m = 1523

divide both sides by 14

\frac{14m}{14} = \frac{1523}{14}

simplify it:

m=\frac{1523}{14}

in simplest form as mixed fraction:

m=108\frac{11}{14}

REY [17]2 years ago
3 0

1523 = 14 m

Exchange sides:

14m = 1523

Divide both sides by 14

\frac{14m}{14}  =  \frac{1523}{14}

Simplify it:

m =  \frac{1523}{14}

In simplest form as mixed fraction:

m = 108 \frac{11}{14}

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The <em>order of operations</em> says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.

If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...

  (-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8

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Here, we're going to evaluate what you have written according to the usual rules as described above.

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<em>Comment on the arithmetic</em>

Fractions are multiplied and divided in the usual way:

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<em>Comment on fractions and parentheses</em>

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Step-by-step explanation:

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Read 2 more answers
. According to Management Accounting, salary figures for certified management accountants (CMAs) who are in the field less than
Mice21 [21]

Answer:

The Mean is not equal to $31,129.

Step-by-step explanation:

Consider the provided information.

The mean is $31129

Thus, the null hypothesis H_0: \mu = 31129

Alternative hypothesis H_a: \mu \neq 31129

A random sample of 15 firstyear CMAs in Denver produces a mean salary of $32,279, with a standard deviation of $1,797.

Thus the value mean of sample is 32279, standard deviation is 1797 and number of samples are 15.

Now use the 2 sided t-test.

t=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

Now substitute the respective values in the above formula.

t=\frac{32279-31129}{\frac{1797}{\sqrt{15}}}

t=\frac{1150}{464}

Test Value = 2.4785  approximately

Now, find the corresponding p-value in your t-table with DF(degree of freedom) 14.

p = 0.0265  

as the value of  p < 0.05, so you reject null hypothesis.  

Thus, the Mean is not equal to $31,129.

7 0
3 years ago
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