The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :


We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
brainly.com/question/10633821
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Answer:
y = -3x - 2
Step-by-step explanation:
slope (m) = (-8 - -5) / (2 - 1) ... difference of y/difference of x
m = -3
y = mx + b
y = -3x + b
for (3,-11) b = y + 3x = -11 + 3x3 = -2
equation: y = -3x - 2
You answer this problem bye cost i already got my answer though thanks for trying...
Answer:
6
Step-by-step explanation:
Straight line is 180
square = right angle=90
180-90=90
5x+(x+54)=90
6x+54=90
6x=36
x=6
Hope this helps :D