Yes, percent is a number.
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
-105
Multiply first, then subtract, then add.
Answer:
The coordinates of ABCD after the reflection across the x-axis would become:
Step-by-step explanation:
The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:
- x-coordinate of the point does not change, but
- y-coordinate of the point changes its sign
In other words:
The point P(x, y) after reflection across x-axis would be P'(x, -y)
P(x, y) → P'(x, -y)
Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:
P(x, y) → P'(x, -y)
A(2, 3) → A'(2, -3)
B(5, 5) → B'(5, -5)
C(7, 3) → C'(7, -3)
D(5, 2) → D'(5, -2)
Therefore, the coordinates of ABCD after the reflection across the x-axis would become:
Answer A because of the absolute value sign.
