Question

WILL GIVE A BRAINLEST TO RIGHT ANSWER

Answer 1

we know that

In the right triangle ABC

∠CAB=∠ABC=$45\°$

so

$AC=CB$

we have

$AB=9\ units$

using sines

 $sin(45\°)=\frac{BC}{AB}$  or  $sin(45\°)=\frac{AC}{AB}$

substitute the value of AB

$sin(45\°)=\frac{BC}{9}$  or  $sin(45\°)=\frac{AC}{9}$

using cosines

$cos(45\°)=\frac{AC}{AB}$  or  $cos(45\°)=\frac{BC}{AB}$

substitute the value of AB

$cos(45\°)=\frac{AC}{9}$  or  $cos(45\°)=\frac{BC}{9}$

therefore

the answer is

$sin(45\°)=\frac{BC}{9}$

$cos(45\°)=\frac{BC}{9}$

Answer 2

Answer:

sin(45)=BC/9     then    cos(45)=BC/9

Step-by-step explanation:

A and E on Edgenuity