What is the value of x? 6.25+3/8x=13 1/4

A cylinder has a height of 17 millimeters and a radius of 6 millimeters. What is its volume? Use ≈ 3.14 and round your answer

lozanna [386]

Answer:

1921.68mm^3

Step-by-step explanation:

Given data

H=17 millimeters

R=6 millimeters.

We know that the expression for the volume of cylinder is

V= πr^2h

substitute

V= 3.14*6^2*17

V= 3.14*36*17

V= 1921.68 mm^3

Hence the volume is 1921.68mm^3

8 0

3 years ago

Write an equation to represent the following statement. j is 25 more than 3 Solve for j

OverLord2011 [107]

Answer:

j=3+25, here's the equation

Step-by-step explanation:

J=28

5 0

3 years ago

Read 2 more answers

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Part b) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

3 years ago

3^4x-5=(1/27) PLEASE HELP I AM IN TEARS

g100num [7]

x = 136/2187 = 0.062

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

3^4*x-5-(1/27)=0

Step by step solution :
Step 1 : 1 Simplify —— 27 Equation at the end of step 1 : 1 (((34) • x) - 5) - —— = 0 27 Step 2 :

Equation at the end of step 2 : 1 ((34 • x) - 5) - —— = 0 27 Step 3 :Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using 27 as the denominator :

81x - 5 (81x - 5) • 27 81x - 5 = ——————— = —————————————— 1 27

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(81x-5) • 27 - (1) 2187x - 136 —————————————————— = ——————————— 27 27 Equation at the end of step 3 : 2187x - 136 ——————————— = 0 27 Step 4 :When a fraction equals zero : 4.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

2187x-136 ————————— • 27 = 0 • 27 27

Now, on the left hand side, the 27 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
2187x-136 = 0

Solving a Single Variable Equation :

4.2 Solve : 2187x-136 = 0

Add 136 to both sides of the equation :
 2187x = 136
Divide both sides of the equation by 2187:
 x = 136/2187 = 0.062

One solution was found : x = 136/2187 = 0.062

8 0

3 years ago

Read 2 more answers

Find the mean of the number set. 93, 81, 94, 78, 89, 92, 94, 99 Your answer divided by 7

dimaraw [331]

Answer:

mean= 90

Step-by-step explanation:

The mean is the terms added together, then divided by the number of terms (in this case, 8):