Answer:
Step-by-step explanation:
What is the perimeter of a quadrilateral with vertices at (1,5), (6,5),
(1,11), and (6,11)? Enter the answer in the box.
f(x)=3x^2-18x+10
a = 3, b = -18 and c = 10
The vertex of a parabola is in form a(x+d)^2 + e
d = b/2a = -18/2(3) = -18/6 = -3
e = c-b^2/4a = 10 - -18^2/4(3) = 10-27 = -17
Now the vertex form of the parabola becomes 3(x-3)^2 -17
Use the vertex form of the parabola in the vertex form of y = a(x-h)^2 +k
Where a = 3, h = -3 and k = -17
Now you have y = 3(x-(-3))^2 +(-17)
Simplify: y = 3(x+3)^2 -17
The vertex becomes the h and k values of (3,-17)
Answer:
-4a+48
Step-by-step explanation:
Using the distributive property, you would multiply -4 with the values inside the brackets, which are a and -12.
-4*a + (-4*(-12))
= -4a+(48)
= -4a+48
Hope this helps!
Answer:
1. X axis, 8, 3
2. Y axis, 4,-9
Step-by-step explanation:
The rule of reflections that the place opposite of the axis is negative so:
The rule for x-axis reflection is (x,-y)
The rule for y-axis is (-x,y)
For the first one, x has remained the same, so that means it’s a x-axis reflection.
So change -3 to 3
Same for the next one.
-9 is not changed so that means it’s a y-axis reflection.
And the point is 4,-9
Increases by 3 each time
aritmetic sequence, firsrt term is 34, 3=common differnce
an=a1+d(n-1) is da formlua
a1=first term
d=common differnce
an=34+3(n-1)
so 32n'd term is
a32=34+3(32-1)
a32=34+3(31)
a32=34+93
a32=127
the 32nd term is 127
