Answer:
Inverse of y=x^3 is f^-1(x) = ∛x
Step-by-step explanation:
We need to find the inverse of y=x^3
Step 1:
Interchange the variables:
x= y^3
Step 2: Now solve to find the value of y
=> y^3 = x
taking cube root on both sides of the equation
∛y^3 = ∛x
y=∛x
Step 3: Replace y with f^-1(x)
f^-1(x) = ∛x
So inverse of y=x^3 is f^-1(x) = ∛x
Answer:
square root of 26 (sorry couldn't get the symbol)
Step-by-step explanation:
C^2 = A^2 + B^2 (Pythagoras Theorem)
C^2 = 5^2 + 1^2
C^2 = 26
take square root of both sides
C =
repeating fraction, nice
2.16161616...=2+0.16161616...
solve the repeating part
let's say x=0.16161616
2 places repeat, multiply x by 10^2 or 100
100x=16.161616
now subtract x from taht
100x-x=16.161616-0.16161616
the repeats cancel and we get
99x=16
divide both sides b 99
x=16/99
so
16/99=0.16161616...
2+16/99 is the fraction
if ya wanted 1 fraction then
2+16/99=
198/99+16/99=
214/99
2.161616=214/99
18 that question is confusing so I guessed sorry dude
Answer:
Step-by-step explanation:
9h+5h(5h-5760)-2+12=y
