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2 years ago

1) Complete the sentences to explain how to multiply 4.56 x 1,000.

Mathematics

1 answer:

S_A_V [24]2 years ago

4 0

Answer:

The decimal point should be moved 3 units to the right, and the result of the multiplication is 4560.

Step-by-step explanation:

Multiplication of a decimal by the nth power of 10:

In this case, the decimal point should be moved n units to the right.

Division of a decimal by the nth power of 10:

In this case, the decimal point should be moved n units to the left.

In this question:

We multiply the decimal 4.56 by 1000.

1000 is the 3rd power of 10, because $10^3 = 1000$ . So the decimal point should be moved 3 units to the right, and the result of the multiplication is 4560.

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Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

A function is defined by f (x) = 5 (2 minus x). What is f(–1)? –5 5 15 53

Helen [10]

Answer:

f(-1) = 15

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 5(2 - x)

Step 2: Evaluate

Substitute in x [Function f(x)]: f(-1) = 5(2 - -1)
(Parenthesis) Subtract: f(-1) = 5(3)
Multiply: f(-1) = 15

5 0

3 years ago

Read 2 more answers

Will give Brainly lollllllll XD......................

marshall27 [118]

Answer:

it looks like it would just be -1

Step-by-step explanation:

there two -x and two positive x which would cancel out. three positive 1 and four negative 1. -4+3= -1

that's the best I could come up with

6 0

2 years ago

Read 2 more answers

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago