The value of the car is January 2003 is $199,148.54.
<h3>What is the value of the car?</h3>
Depreciation is the rate of decline in the value of an asset with the passage of time.
The exponential equation that can be used to determine the value of the car is:
Value of the car = purchase value(1 - rate of decline)^time
400,000 x (1 - 0.16)^(2003 - 1999)
400,000 x (0.84^4) = $199,148.54
To learn more about depreciation, please check: brainly.com/question/15085226
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The answer is C
The length of a,b is 15
The length of j,m is 10
The width of d,c is 5
The width of m,l is 6
Length over length does not equal
Width over width
LCD ( 3 * 4 ) = 12
Multiply by LCD = 12
Refine :
Subtract 8 from both sides:
Divide both sides by 9
hope this helps!
Answer:
0.3085,0.2417,0.0045
Step-by-step explanation:
Given that X, the amount of money spent at shopping centers between 4 P.M. and 6 P.M. on Sundays has a normal distribution with mean $85 and with a standard deviation of $20.
X is N(85, 20)
To convert into std normal variate we use the following formula
a) the probability that he has spent more than $95 at the mall
=
b. the probability that he has spent between $95 and $115 at the mall
=
c. If two shoppers are randomly selected, what is the probability that both shoppers have spent more than $115 at the mall
=product of two probabilities since independent
=