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HACTEHA [7]
3 years ago
12

Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

Mathematics
1 answer:
oee [108]3 years ago
8 0
The answer is \frac{x^{4/3}y^{3}}{3}.

The fraction is: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5}  }
Let's rewrite it: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }

Since \frac{x^{a} }{x^{b}} =x^{a-b},
then:
*** \frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}
*** \frac{y^{-2} }{ y^{-5} }=  y^{-2-(-5)} = y^{-2+5} = y^{3}
______
\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}
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What is the simplified form of the quantity y-squared plus 7y plus 12 over the quantity y-squared plus 8y plus 15
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Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.

7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)

Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.

Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.

This gives us our final answer:
(y+4)/(y+5)
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a person being asked what his age was replied that 3/4 of his age multiplied by 1/12 of his age gave a product equal to his age.
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Answer:

0.0625

Step-by-step explanation:

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there is 7 possible solutions

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A basketball player made 52 out of 100 attempted free throws. What percent of free throws was made?
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Answer:

The function y = -x whose reflection in the line y =x is itself.

Step-by-step explanation:

A reflection that maps every point of a figure to an image across a fixed line. Then the fixed line is called the line of reflection.

The reflection of the point (x,y)  in the line y = x is the point (y, x).

Therefore, the  function y = -x  whose  reflection in the line y =x is itself.

Symmetries of the function f(x)= -x is:    

A function symmetric with respect to the y-axis is called an even function.

If f(-x) = f(x)

A function that is symmetric with respect to the origin is called an odd function.

if f(-x) = -f(x)

then, we must look at f(-x);

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f(-x)= -(-x)= x = -f(x)

this function is symmetrical to with respect to origin.

Therefore, this function is an odd function.





 

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3 years ago
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