Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
x = perimeter
x<156
length = 66
so, in order to calculate perimeter you need to add two lengths and two widths
so
156 (perimeter) - 2 (66) = two widths
156 - 132 = 24 (remember this number is two widths added together)
so 24 twice the width SO 12 would be the number that the width can't be larger than
the width has to be less than 12
w < 12
Answer:
49 - x^2
Step-by-step explanation:
(7+x)(7-x)
We know this is the difference of squares
(a-b) (a+b) = a^2 - b^2
7^2 - x^2 = 49-x^2
We can also FOIL
first = 7*7 = 49
Outer: = 7x
Inner: = -7x
Last : -x*x = -x^2
Add them together
49 +7x-7x - x^2
Combine like terms
49-x^2
Answer:
B
Step-by-step explanation:
The value of x is 34.64 feet
<h3>Right-angled triangle</h3>
Find the diagram attached
- The height of the tent = 40 ft
- length of the rope = x
Get the value of x using the SOH CAH TOA identity
Hence the value of x is 34.64 feet
Learn more on SOH CAH TOA here: brainly.com/question/20734777
