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morpeh [17]
2 years ago
12

What is a true statement comparing the graphs of x^2/6^2 = 1 and x^2/8^2-y^2/6^2=1

Mathematics
1 answer:
Jlenok [28]2 years ago
4 0

I am assuming that the statements are as follows:

The foci of both graphs are the same points.

The lengths of both transverse axes are the same.

The directrices of = 1 are horizontal while the directrices of = 1 are vertical.

The vertices of = 1 are on the y-axis while the vertices of = 1 are on the x-axis.

It should be A because of

Edge 21.

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Solve the equation sine Ф=0.6792 for 0°≤Ф≤360
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Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

180 - 42.78

= 137.33 degres.

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Tax is paid on meals in a restaurant.
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Answer:

17.52%

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.1752 * 100

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Read 2 more answers
A person borrowef Rs 16000 from a bank at 12.5% pet annum simple intrest and lent the whole amount to shopkeeper at the sam rate
r-ruslan [8.4K]

Answer:

The amount he gains in 2 years is Rs. 250

Step-by-step explanation:

The parameters of the amount borrowed from the bank are;

The amount borrowed, P = Rs. 16,000

The interest rate of the amount borrowed, R = 12.5%

The number of years, T = 2 years

The simple interest, I = (P × R × T)/100 =  (Rs. 16,000 × 12.5 × 2)/100 = Rs. 4,000

The total amount the person is to pay bank to the bank = P + I = Rs. 16,000 + Rs. 4,000 = Rs. 20,000

The parameters of the amount lent to the shopkeeper are;

The amount lent, P = Rs. 16,000

The compound interest rate of the amount lent, R = 12.5%

The number of years, T = 2 years

The amount he receives from the shopkeeper after 2 years, A = P·(1 + R/n)^(n × T) = Rs. 16,000 × (1 + 0.125/1)^(1 × 2) = Rs. 20,250

The amount he gains in 2 years = The amount he receives from the shop keeper - The amount he gives to the bank = Rs. 20,250 - Rs. 20,000 = Rs. 250

The amount he gains in 2 years = Rs. 250.

8 0
2 years ago
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