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2 years ago

Which transformation shows a translation of 3 units to the right? A)A B)С C)B D)D

Mathematics

1 answer:

Citrus2011 [14]2 years ago

4 0

Answer:

Step-by-step explanation: It`s option C

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Frederick is half as tall as his older sister his older sister is 62 inches tall write an equation to represent Frederick's heig

garri49 [273]

F = 1/2s
s = 62

f = 1/2(62) or f = 62/2 <===

5 0

2 years ago

4 × (h ×5) = (4 × h) ×5

Sholpan [36]

Answer:c.

Commutative Property of Multiplication

Step-by-step explanation:

5 0

2 years ago

PLEASE HELP!!

user100 [1]

(8/-4) / (-3/9)=

(8/-4) * (9/3)=

72/-12=

-6

6 0

3 years ago

Jordan's family traveled 3/8 of the distance to his grandfather's house on Saturday. They traveled 3/5 of the remaining distance

jarptica [38.1K]

Answer:

1/40

Step-by-step explanation:

You have to find the amount of distance they traveled since the start of the journey. 3/5 + 3/8 is 39/40. How did we get that, you may ask?

We need to find a number that both 5 and 8 have to make. That can be 40. But how we made 5 and 8 40, we need to do the same to the top numbers. So 39/40 when we add them up. Finally, we need to substract that from the whole, and this gets you 1/40. Hope this helps.

Have a wonderful day, my friend.

4 0

3 years ago

According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a

Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, $\mu$ = 2.58 and Standard deviation, $\sigma$ = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar $\leq$ 2.50)

P(Xbar < 2.66) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z < -1.68) = 1 - P(Z 1.68)

= 1 - 0.95352 = 0.04648

P(Xbar $\leq$ 2.50) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z $\leq$ -3.92) = 1 - P(Z < 3.92)

= 1 - 0.99996 = 0.00004

Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046

7 0

3 years ago