The issue arises because the string you are trying to print is not a string, rather a float value. Item1, item2 and item3 are strong values (if you type some alphabets in it and not just numbers), but itemonecost, itemtwocost, and itemthreecost are explicitly type casted to float. In line 22, 23, and 24 you’re trying to print a float, by adding it with the string. One cannot add numbers to string. Rather you can type cast the itemcost to string while printing.
Add str(itemonecost) instead of itemonecost in print statement. Do this for other float variables too.
However do note that there are multiple ways to correct this issue, and I’ve just pointed one out.
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
Answer:b)The item’s classification and category set
Explanation: Mandatory access control(MAC) is the security component in the computer system. It is regarding the controlling the access of the operating system by the administrator.The accessing is made limited by the MAC according to the sensitivity of the data .
The authorization for user to access the system is based on this sensitivity level known sensitivity label. The objects contain the information regarding the classification and categories or level of items. Thus, the correct option is option(b).
I think its c I hope I'm not wrong about this If I am I'm sorry
are you using windows? linux? mac?
