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In-s [12.5K]
3 years ago
12

Heeelelppppppp it is area of a circle help me plz i will make you the brillientest

Mathematics
1 answer:
LiRa [457]3 years ago
6 0
18.84 I think you have to do the math from the radius to the edge of the circle
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Please help if you would like brianleist! (No links please!) Thank you! :) have a great day as well! :)
Arlecino [84]

The answer to your question would be C.

5 0
3 years ago
Read 2 more answers
What are the last 2 digits of 7 to the power of 2018. This question was on a past exam paper.
Xelga [282]

Answer:

49

Step-by-step explanation:

  • Try finding pattern of last two digits of 7 to the power of some numbers.

7^1=07

7^2=49

7^3=343

7^4= 2301

7^5= 16807

  • so , the pattern is, 07,49,43,01
  • so, if we start writing all numbers from 1 to 2018 , four number in each line, 2018 will fall in the second column.
  • so it will have 49 as the  last 2 digits [by seeing this pattern : 07,49,43,01 ]
6 0
3 years ago
Chris paid $36 for 3 tanktops and 2 shirts. a shirt cost 3 times as much as a tank top. how much did chris pay for the 2 shirts?
devlian [24]

Answer:

$72

Step-by-step explanation:

36/3=12

1 tanktop=$12

12*3=36

1 shirt equals=$36

36*2=72

2 shirts=$72

4 0
3 years ago
PLZ HELP ASAP!!!!!!!!!!!
lorasvet [3.4K]
For number 3 add all the numbers and divide how numbers you have
5 0
3 years ago
Read 2 more answers
What are the next three terms in the pattern 2, 6, 18, 54, ...?
castortr0y [4]

Answer:

OPTION B: 162, 486, 1458

Step-by-step explanation:

The given sequence is 2, 6, 18, 54, . . .

It is a geometric sequence and the common difference is 3.

The general form of a geometric sequence is: a, ar, ar², ar³, . . .

Here a = 2 and r = 3.

$ n^{th} $ term of a Geometric progression is $ ar^{n - 1} $.

Note that the fourth term is 54.

i.e., $ ar^3 = 54 $

$ \implies ar^4 = ar^3 . r = 54 . 3 = 162 $.

Similarly, $ ar^6 = 162 \times 3 = 486 $.

Also, $ ar^7 = ar^6 . r = 486 \times 3 = 1458 $.

Hence, OPTION B is the answer.

8 0
3 years ago
Read 2 more answers
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