Answer:
3 / 91
Step-by-step explanation:
Given :
Red balls = 3
Blue balls = 4
Green balls = 4
Yellow balls = 3
Total number of balls = (3+4+4+3) = 14
Sample space :
RR, BB, GG, YY, RB, BR, BG, GB, YG, GY, YR, RY, BY, YB, GR, RG
Probability of drawing two red balls without replacement :
1st draw :
P(red) = number of red balls / total number of balls
P(red) = 3/14
2nd draw :
P(red) = 2 / 13
Hence,
P(RR) = 3/14 * 2/13 = 6 / 182 = 3 / 91
