9514 1404 393
Answer:
- 7.5 ft
- 32.5 ft, 5 ft
- 10.7 ft
Step-by-step explanation:
a) The starting height is h(0) = 7.5 feet, the constant in the quadratic function.
The irrigation system is positioned <u> 7.5 </u> feet above the ground
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b) The axis of symmetry for quadratic ax^2 +bx +c is x = -b/(2a). For this quadratic, that is x=-10/(2(-1)) = 5. This is the horizontal distance to the point of maximum height. The maximum height is ...
h(5) = (-5 +10)(5) +7.5 = 32.5 . . . feet
The spray reaches a maximum height of <u> 32.5 </u> feet at a horizontal distance of <u> 5 </u> feet from the sprinkler head.
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c) The maximum distance will be √32.5 + 5 ≈ 10.7 ft.
The spray reaches the ground at about <u> 10.7 </u> feet away.
<span>{<span>xi</span>,...}</span><span>|3|≥x</span>something like this
Answer:
y = 6/5x
Step-by-step explanation:
1. 
2. subtract the two number on the top of the fraction bar to get 6
3. do the same for the denominator to get 5
4. your final answer is 
Answer:
<em>π/2 and π/3</em>
Step-by-step explanation:
Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.
let P = cosx
The equation becomes 2P²-P = 0
P(2P-1) = 0
P = 0 and 2P-1 = 0
P= 0 and P = 1/2
Since P = cosx
cosx = 0 and cos(x) = 1/2
If cos(x) = 0
x = cos⁻¹0
x = 90⁰
x = π/2
If cos(x) = 1/2
x = cos⁻¹1/2
x = 60⁰
x = π/3
<em>Hence the solutions to the equation are π/2 and π/3.</em>