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3 years ago

1. What is the equation in point-slope form of the line that has a slope of 1/3 and passes through the point (12, 5)?

Mathematics

1 answer:

Margaret [11]3 years ago

4 0

Answer:

Step-by-step explanation:

because the mass

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zysi [14]

Change the x and y
Then solve for y
X= 8y+1
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X-1=8y
Divide by 8
X-1 /8 = y

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3 years ago

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, the

san4es73 [151]

Answer:

We get value of the value of b = 5

Step-by-step explanation:

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, then m=m equals negative StartFraction 1 Over 6 EndFraction.. What is the value of b?

We have slope m: $m=-\frac{1}{6}$

We need to find value of b (y-intercept)

Using the point A(-6,6) and slope $m=-\frac{1}{6}$ we can find b.

Using slope-intercept form, putting values of m and x and y we get the value of b:

$y=mx+b\\6=-\frac{1}{6}(-6)+b\\6=1+b\\b=6-1\\b=5$

So, we get value of the value of b = 5

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3 years ago

Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter

andreev551 [17]

Answer:

Step-by-step explanation:

In each case, draw the right triangle which produces the inverse trig value. That is, label the two sides as needed, and calculate the third side.

It should be clear that

$tan(sin^{-1} x/4) = x/\sqrt{16-x^{2} }$

$sin(tan^{-1} x/4) = x/\sqrt{16+x^{2} }$

sin(2α) = 2 sinα cosα

So,

$1/2 sin(2sin^{-1} x/4) = (1/2)(x/4) * x/\sqrt{16-x^2} = x^{2} /(8\sqrt{16-x^2})$

See what you can do with the others.

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3 years ago

True or False?

dsp73

Answer:

true

Step-by-step explanation:

i go to k12 i did this test

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2 years ago

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Irina-Kira [14]

Answer:

44 cm

Step-by-step explanation:

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