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Answer:
3 < b-a < 7
Step-by-step explanation:
The maximum difference will occur when the smallest 'a' value is subtracted from the largest 'b' value:
9 -2 = 7
The minimum difference will occur when the largest 'a' value is subtracted from the smallest 'b' value:
7 -4 = 3
So, the possible range of values of b-a is ...
3 < b-a < 7
A. -25/36
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Answer:
5
Step-by-step explanation:
For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.
Also, two physically quantities can only be added or subtracted only when their dimension are same.
here all option are dimensionally correct except the 5th option where
dimension of t= [T] whereas dimension of a/v is 
= T^{-1}
since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2