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3 years ago

HELP!! Im Working on homework and not sure how to do this and its due tomorrow can anyone help me!! Btw it’s geometry!

Mathematics

1 answer:

Dmitrij [34]3 years ago

3 0

Answer:

1. 7.3

2. 33.3

3. 9.2

4.31.9

5.25.6

6.11

7.42°

8.64°

9.13°

10. 51°

Step-by-step explanation:

Hope this helps.

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How do I write an equation that would allow someone to find the value of R

Ivahew [28]

Answer:

R+239=3501

Step-by-step explanation:

Add the three 1,167 values together and you get 3,501. Then, because we know a portion of the three blocks is equal to 239, add it so when we solve for R, 239 is subtracted from the total.

As for solving it,

Subtract 239 on both sides, and R is 3501-239 = <u>3262</u>

6 0

3 years ago

If 12 newborn babies are randomly selected, how many different gender sequences are possible?

ki77a [65]

If there are 2 genders it's 2^12, which is 4096

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3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then