The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
s = (1/2)√(a²+b²)
Answer:
B
Step-by-step explanation:
58×20=1160
0+160+1000=1160
5 - 6 = -1
2 + 7 = 9
-1 × 9 = -9
-9 would be the simplified answer.
Hope this helps!
Answer:
1) Distribute 1.2 to 6.3 and -7x
2)Combine 3.5 and 7.56
3)Subtract 11.06 from both sides
Step-by-step explanation:
3.5 + 1.2(6.3 - 7x) = 9.38
Distribute 1.2 to 6.3 and -7x
3.5 + 1.2* 6.3 - 1.2 * 7x = 9.38
3.5 + 7.56 - 8.4x = 9.38
Combine 3.5 and 7.56
11.06 - 8.4x = 9.38
Subtract 11.06 from both sides
11.06 - 8.4x -11.06 = 9.38 - 11.06
-8.4x = -1.68
To find solution:
Divide both sides by (-8.4)
-8.4x/-8.4 = -1.68/-8.4
x = 0.02
You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.