Given two points (x₁,y₁) and (x₂,y₂), the midpoint of the segment will be:
( (x₁+x₂) / 2 , (y₁+y₂)/2 ).
In this case:
J(-3,18)
T(7,-10)
The midpoint will be:
( (-3+7)/2 , (18-10)/2 )=(4/2 , 8/2)=(2, 4).
Answer: the midpoint of segment JT is (2,4)
(-3, 6) includes all numbers between -3 and 6 but it does not include -3 and 6.
when you put square parentheses you include the number on the edge
so if an anwser includes all numbers between -3 and 6 and the number 6 it's correct to write (-3,6]
Answer:
112
Step-by-step explanation:
I'd use synthetic div. here, with 2 as my divisor:
________________
2 / 1 -11 18
2 -18
----------------------------
1 -9 0
Note that the coefficients of the missing factor are given here and are 1 and -9. Thus, (x-9) is the missing factor.
