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boyakko [2]
3 years ago
11

For your trouble answering this, you will get 30 points. for all the trouble this may cause.

Mathematics
1 answer:
Gennadij [26K]3 years ago
7 0

Answer:

read below

Step-by-step explanation:

A1: I think D because you have a medium average mix of concentrate that will mix with only 2 more cups than itself, so this would keep it fine. A could also work sooooo.... A or D. i dont know at this point. B COULD be a possible solution but it's 5 vs 9.

A2: C

1 cup of concentrate vs 2 water.... the water will make it MUCH more of a clear color.

Question C: this is more time consuming and I am tired so for you this might be easier if you're not as tired so based on what I'm reading you need to do math for each of the 4 options above, concentrate and water mix, and then divide the total of the 2 types of cups for every option.

Hope Q1 and Q2 helped though!

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Question 16....please help me out
Varvara68 [4.7K]

Answer:

Persian-Maine Coon-American Shorthair

Step-by-step explanation:

If you look back at the question, you will see the numbers 13.65,13.07, and 13.6. So, we'll do this by digits.

The first digit of all the numbers is 1. So we'll move on. The second digit is a3, of which all numbers have in common. So we'll move on again. So now ur down to the digits 6, 0, and 6. Well, 13.07 belongs to the Persian. Then You'll see a 6, which belongs to the Maine coon. Lastly, you have another 6, which goes to the American shorthair. Correct me if i'm wrong :-)

5 0
3 years ago
HELP!!! I dont understand this!!! (BRAINLIEST)
Elden [556K]
I think it’s b also
6 0
3 years ago
Suppose r(x) and t(x) are two functions with the same domain, and let h(x)=r(x)+t(x).
Sphinxa [80]

Answer:

If the maximum of function r(x) and t(x) occur at the same point c in domain P = max(r(x)+t(x)) = M+N

In general P  ≤  M+N

Step-by-step explanation:

If the maximum of function r(x) and t(x) occur at the same point c in domain then M=r(c) and N=t(c) So in this case P = max(r(x)+t(x)) = M+N

In general P  ≤  M+N

by definition of maximum  

r(x)≤M,t(x)≤N   for all x in domain

=>  r(x)+t(x)≤M+N   for all x in domain

=> max(r(x)+t(x)) <= M+N

=> P  ≤  M+N

Thus we get in general the relationship is P  ≤  M+N

4 0
3 years ago
If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter
zloy xaker [14]
Distance formlula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=\sqrt{(3-(-3))^{2}+(5-3)^{2}}=2√10

c to d is (3,5) to (-1,0)
D=\sqrt{(-1-3)^{2}+(0-5)^{2}}=√41

d to b is (-1,0) to (-3,3)
D=\sqrt{(-3-(-1))^{2}+(3-0)^{2}}=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units





7 0
3 years ago
Daca adun sfertul lui a cu jumatatea lui b si cu treimea lui c, obtin 120. Stiind ca jumatatea lui b este cu 24 mai mare decat s
schepotkina [342]

Answer:

Step-by-step explanation:

Dacă adaug un sfert de la jumătate de b și o treime de c, obțin 120.

Aceasta se exprimă ca:

1 / 4a + 1/2 b + 1 / 3c = 120 ..... Ecuația 1

Știind că jumătate din b este de 24 de ori mai mare decât un sfert de a

1 / 2b = (1/4 × a) 24

b / 2 = (a / 4) 24

b / 2 = 6a

Cross Multiply

b = 6a × 2

b = 12a

a = b / 12

Jumătate din b este de 4 ori mai mare decât o treime din c

1/2 × b = 4 × (1/3 × c)

b / 2 = 4 (c / 3)

b / 2 = 4c / 3

Cross Multiply

b = 2 × 4c / 3

b = 8c / 3

8c = 3b

c = 3b/8

1 / 4a + 1/2 b + 1 / 3c = 120 ..... Ecuația 1

Înlocuim

1/4 × b / 12 + 1 / 2b + 1/3 × 3b / 8= 120

b / 48 + b / 2 + b/8 = 120

Înmulțiți cu 48

b/48 × 48 + b/2 × 48 + b/8× 48 = 120 × 48

b + 24b + 6b = 5760

31b = 5760

6 0
3 years ago
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